What is the integral of tan(x)cos(x) ?

The integral of tan(x)cos(x) is -cos(x)+C

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integral of tan(x)cos(x)

\int tan (x) cos (x) d x

- cos (x) + C

Solution steps

\int tan (x) cos (x) d x

Express with sin, cos

= \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - cos (x)

Add a constant to the solution

= - cos (x) + C

\frac{d}{d x} ((8 - x)^{3})

\int \frac{1}{2 + x ^{2}} d x

x \to 4 lim (\frac{x ^{2} - 16}{2 x ^{2} + 7 x - 4})

sin (2 x) d x + cos (5 y) d y = 0

\frac{d}{d x} (ln (x^{2}) + y^{2} - 1)

What is the integral of tan(x)cos(x) ?
The integral of tan(x)cos(x) is -cos(x)+C