What is the derivative of (8-x^3) ?

The derivative of (8-x^3) is -3(8-x)^2

What is the first derivative of (8-x^3) ?

The first derivative of (8-x^3) is -3(8-x)^2

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\frac{d}{d x} ((8 - x)^{3})

- 3 (8 - x)^{2}

Solution steps

\frac{d}{d x} ((8 - x)^{3})

Apply the chain rule:

3 (8 - x)^{2} \frac{d}{d x} (8 - x)

= 3 (8 - x)^{2} \frac{d}{d x} (8 - x)

\frac{d}{d x} (8 - x) = - 1

= 3 (8 - x)^{2} (- 1)

Simplify

= - 3 (8 - x)^{2}

\int \frac{1}{2 + x ^{2}} d x

x \to 4 lim (\frac{x ^{2} - 16}{2 x ^{2} + 7 x - 4})

sin (2 x) d x + cos (5 y) d y = 0

\frac{d}{d x} (ln (x^{2}) + y^{2} - 1)

\frac{d}{d x} ((\frac{( 3 x + 1 )}{x ^{2}})^{3})

What is the derivative of (8-x^3) ?
The derivative of (8-x^3) is -3(8-x)^2
What is the first derivative of (8-x^3) ?
The first derivative of (8-x^3) is -3(8-x)^2