What is the integral from-1 to 1 of 10^x ?

The integral from-1 to 1 of 10^x is (99)/(10ln(10))

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integral from-1 to 1 of 10^x

\int_{- 1}^{1} 1 0^{x} d x

\frac{99}{10 ln ( 10 )}

Decimal Notation

4.29951 \dots

Solution steps

\int_{- 1}^{1} 1 0^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{1 0 ^{x}}{ln ( 10 )}]_{- 1}^{1}

Compute the boundaries:

\frac{99}{10 ln ( 10 )}

= \frac{99}{10 ln ( 10 )}

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What is the integral from-1 to 1 of 10^x ?
The integral from-1 to 1 of 10^x is (99)/(10ln(10))