What is the integral of (sin^3(sqrt(x)))/((sqrt(x))) ?

The integral of (sin^3(sqrt(x)))/((sqrt(x))) is 2(-cos(sqrt(x))+(cos^3(sqrt(x)))/3)+C

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integral of (sin^3(sqrt(x)))/((sqrt(x)))

\int \frac{sin ^{3} ( x )}{( x )} d x

2 (- cos (x) + \frac{cos ^{3} ( x )}{3}) + C

Solution steps

\int \frac{sin ^{3} ( x )}{x} d x

Apply u-substitution

: \int 2 sin^{3} (u) d u

= \int 2 sin^{3} (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin^{3} (u) d u

Rewrite using trig identities

= 2 \cdot \int (1 - cos^{2} (u)) sin (u) d u

Apply u-substitution

: \int - 1 + v^{2} d v

= 2 \cdot \int - 1 + v^{2} d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (- \int 1 d v + \int v^{2} d v)

\int 1 d v = v

\int v^{2} d v = \frac{v ^{3}}{3}

= 2 (- v + \frac{v ^{3}}{3})

Substitute back

= 2 (- cos (x) + \frac{cos ^{3} ( x )}{3})

Add a constant to the solution

= 2 (- cos (x) + \frac{cos ^{3} ( x )}{3}) + C

\int_{- 1}^{1} 1 0^{x} d x

(\frac{3}{x})^{^{'}}

\frac{d}{d x} (5 x^{2} ln (x))

(x^{3} - 16 x)^{14}

\int 36 x^{2} d x

What is the integral of (sin^3(sqrt(x)))/((sqrt(x))) ?
The integral of (sin^3(sqrt(x)))/((sqrt(x))) is 2(-cos(sqrt(x))+(cos^3(sqrt(x)))/3)+C