en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

derivative of 8sqrt(4x-1)

Solution

\frac{d}{d x} (8 4 x - 1)

Solution

\frac{16}{4 x - 1}

Solution steps

\frac{d}{d x} (8 4 x - 1)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (4 x - 1)

Apply the chain rule:

\frac{1}{2 4 x - 1} \frac{d}{d x} (4 x - 1)

= \frac{1}{2 4 x - 1} \frac{d}{d x} (4 x - 1)

\frac{d}{d x} (4 x - 1) = 4

= 8 \cdot \frac{1}{2 4 x - 1} \cdot 4

Simplify

8 \cdot \frac{1}{2 4 x - 1} \cdot 4 : \frac{16}{4 x - 1}

= \frac{16}{4 x - 1}

Graph

Popular Examples

limit as x approaches 2 of x^2+a

x \to 2 lim (x^{2} + a)

y^{'''}-3y^{''}+3y^'-y=x

y^{^{'''}} - 3 y^{^{''}} + 3 y^{^{'}} - y = x

integral of (sqrt(x))/2+2/(sqrt(x))

\int \frac{x}{2} + \frac{2}{x} d x

(\partial)/(\partial x)((x+y)/(xy-1))

\frac{\partial}{\partial x} (\frac{x + y}{x y - 1})

(dy)/(dx)=sin(y)+1

\frac{d y}{d x} = sin (y) + 1

Frequently Asked Questions (FAQ)

What is the derivative of 8sqrt(4x-1) ?
The derivative of 8sqrt(4x-1) is (16)/(sqrt(4x-1))
What is the first derivative of 8sqrt(4x-1) ?
The first derivative of 8sqrt(4x-1) is (16)/(sqrt(4x-1))