What is the derivative of 1+3/x ?

The derivative of 1+3/x is -3/(x^2)

What is the first derivative of 1+3/x ?

The first derivative of 1+3/x is -3/(x^2)

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\frac{d}{d x} (1 + \frac{3}{x})

- \frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (1 + \frac{3}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (\frac{3}{x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{3}{x}) = - \frac{3}{x ^{2}}

= 0 - \frac{3}{x ^{2}}

Simplify

= - \frac{3}{x ^{2}}

\int \frac{1}{50 + t} d t

f (x) = 3 t^{4} - 7 t^{3} + 2

x \to 1 lim (sin (3 p i x))

e^{- 20 x}

\frac{d}{d x} (ln (\frac{3 x}{x ^{2} + 4}))

What is the derivative of 1+3/x ?
The derivative of 1+3/x is -3/(x^2)
What is the first derivative of 1+3/x ?
The first derivative of 1+3/x is -3/(x^2)