What is the derivative of 6x^4-3 ?

The derivative of 6x^4-3 is 24x^3

What is the first derivative of 6x^4-3 ?

The first derivative of 6x^4-3 is 24x^3

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derivative of

6 x^{4} - 3

24 x^{3}

Solution steps

\frac{d}{d x} (6 x^{4} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{4}) - \frac{d}{d x} (3)

\frac{d}{d x} (6 x^{4}) = 24 x^{3}

\frac{d}{d x} (3) = 0

= 24 x^{3} - 0

Simplify

= 24 x^{3}

\int x^{4} (x^{5} - 4)^{8} d x

f (x) = \frac{3}{3 x + 1}

\frac{d}{d x} (\frac{x ^{5} + 2 x + 6}{x ^{\frac{1}{3}}})

f (x) = cos (5 x^{2})

\int (y - 1)^{2} d y

What is the derivative of 6x^4-3 ?
The derivative of 6x^4-3 is 24x^3
What is the first derivative of 6x^4-3 ?
The first derivative of 6x^4-3 is 24x^3