What is the derivative of (x^5+2x+6/(x^{1/3)}) ?

The derivative of (x^5+2x+6/(x^{1/3)}) is (14x^5+4x-6)/(3x^{4/3)}

What is the first derivative of (x^5+2x+6/(x^{1/3)}) ?

The first derivative of (x^5+2x+6/(x^{1/3)}) is (14x^5+4x-6)/(3x^{4/3)}

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\frac{d}{d x} (\frac{x ^{5} + 2 x + 6}{x ^{\frac{1}{3}}})

\frac{14 x ^{5} + 4 x - 6}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (\frac{x ^{5} + 2 x + 6}{x ^{\frac{1}{3}}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{5} + 2 x + 6 ) x ^{\frac{1}{3}} - \frac{d}{d x} ( x ^{\frac{1}{3}} ) ( x ^{5} + 2 x + 6 )}{( x ^{\frac{1}{3}} ) ^{2}}

\frac{d}{d x} (x^{5} + 2 x + 6) = 5 x^{4} + 2

\frac{d}{d x} (x^{\frac{1}{3}}) = \frac{1}{3 x ^{\frac{2}{3}}}

= \frac{( 5 x ^{4} + 2 ) x ^{\frac{1}{3}} - \frac{1}{3 x ^{\frac{2}{3}}} ( x ^{5} + 2 x + 6 )}{( x ^{\frac{1}{3}} ) ^{2}}

Simplify

\frac{( 5 x ^{4} + 2 ) x ^{\frac{1}{3}} - \frac{1}{3 x ^{\frac{2}{3}}} ( x ^{5} + 2 x + 6 )}{( x ^{\frac{1}{3}} ) ^{2}} : \frac{14 x ^{5} + 4 x - 6}{3 x ^{\frac{4}{3}}}

= \frac{14 x ^{5} + 4 x - 6}{3 x ^{\frac{4}{3}}}

f (x) = cos (5 x^{2})

\int (y - 1)^{2} d y

\frac{\partial}{\partial x} (4 y e^{x})

\frac{d}{d θ} (tan (θ))

\frac{d}{d x} (x \cdot y)

What is the derivative of (x^5+2x+6/(x^{1/3)}) ?
The derivative of (x^5+2x+6/(x^{1/3)}) is (14x^5+4x-6)/(3x^{4/3)}
What is the first derivative of (x^5+2x+6/(x^{1/3)}) ?
The first derivative of (x^5+2x+6/(x^{1/3)}) is (14x^5+4x-6)/(3x^{4/3)}