What is the tangent of y= 1/(2+3x),(1, 1/5) ?

The tangent of y= 1/(2+3x),(1, 1/5) is y=-3/25 x+8/25

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tangent of y= 1/(2+3x),(1, 1/5)

tangent of

y = \frac{1}{2 + 3 x}, (1, \frac{1}{5})

y = - \frac{3}{25} x + \frac{8}{25}

Solution steps

Find the slope of

y = \frac{1}{2 + 3 x} : \frac{d y}{d x} = - \frac{3}{( 2 + 3 x ) ^{2}}

Compute the slope of

y = \frac{1}{2 + 3 x}

(1, \frac{1}{5}) : m = - \frac{3}{25}

Find the line with slope m=

- \frac{3}{25}

and passing through

(1, \frac{1}{5}) : y = - \frac{3}{25} x + \frac{8}{25}

y = - \frac{3}{25} x + \frac{8}{25}

x \to + 2 lim (e^{\frac{1}{x - 2}})

(- 4 sin (2 x))^{^{'}}

f (x) = \frac{20}{( x + 3 ) ^{2}}

\frac{d}{d x} (8^{c o s (x)})

f (x) = - x^{2} + 4 x, at x = 3

What is the tangent of y= 1/(2+3x),(1, 1/5) ?
The tangent of y= 1/(2+3x),(1, 1/5) is y=-3/25 x+8/25