What is (\partial)/(\partial y)(3x^2y^2+x/y) ?

The answer to (\partial)/(\partial y)(3x^2y^2+x/y) is 6x^2y-x/(y^2)

Popular >

(\partial)/(\partial y)(3x^2y^2+x/y)

\frac{\partial}{\partial y} (3 x^{2} y^{2} + \frac{x}{y})

6 x^{2} y - \frac{x}{y ^{2}}

Solution steps

\frac{\partial}{\partial y} (3 x^{2} y^{2} + \frac{x}{y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2} y^{2}) + \frac{\partial}{\partial y} (\frac{x}{y})

\frac{\partial}{\partial y} (3 x^{2} y^{2}) = 6 x^{2} y

\frac{\partial}{\partial y} (\frac{x}{y}) = - \frac{x}{y ^{2}}

= 6 x^{2} y - \frac{x}{y ^{2}}

x \to 5 lim (4 x + ∣ x - 5 ∣)

n = 1 \sum \infty \frac{x ^{n}}{1 2 ^{n}}

\frac{d}{d t} (cos (t))

\frac{d y}{d x} + sin^{2} (x) y = cos^{2} (x) y

y = \frac{1}{2 + 3 x}, (1, \frac{1}{5})

What is (\partial)/(\partial y)(3x^2y^2+x/y) ?
The answer to (\partial)/(\partial y)(3x^2y^2+x/y) is 6x^2y-x/(y^2)