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Popular >

derivative of sin^2(2x-cos(2x))

Solution

\frac{d}{d x} (sin^{2} (2 x) - cos (2 x))

Solution

2 sin (4 x) + 2 sin (2 x)

Solution steps

\frac{d}{d x} (sin^{2} (2 x) - cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin^{2} (2 x)) - \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (sin^{2} (2 x)) = 2 sin (4 x)

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 sin (4 x) - (- sin (2 x) \cdot 2)

Simplify

= 2 sin (4 x) + 2 sin (2 x)

Popular Examples

(\partial)/(\partial y)(3x^2y^2+x/y)

\frac{\partial}{\partial y} (3 x^{2} y^{2} + \frac{x}{y})

limit as x approaches 5 of 4x+|x-5|

x \to 5 lim (4 x + ∣ x - 5 ∣)

sum from n=1 to infinity of (x^n)/(12^n)

n = 1 \sum \infty \frac{x ^{n}}{1 2 ^{n}}

\frac{d}{d t} (cos (t))

(dy)/(dx)+sin^2(x)y=cos^2(x)y

\frac{d y}{d x} + sin^{2} (x) y = cos^{2} (x) y

Frequently Asked Questions (FAQ)

What is the derivative of sin^2(2x-cos(2x)) ?
The derivative of sin^2(2x-cos(2x)) is 2sin(4x)+2sin(2x)
What is the first derivative of sin^2(2x-cos(2x)) ?
The first derivative of sin^2(2x-cos(2x)) is 2sin(4x)+2sin(2x)