derivative of e^{2x}+x^2-16

Lösung

\frac{d}{d x} (e^{2 x} + x^{2} - 16)

2 x + 2 e^{2 x}

Schritte zur Lösung

\frac{d}{d x} (e^{2 x} + x^{2} - 16)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (16)

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (16) = 0

= e^{2 x} \cdot 2 + 2 x - 0

Vereinfache

= 2 x + 2 e^{2 x}

\int_{0}^{2} (1 + 3 x^{2}) d x

in v erse l a pl a ce \frac{s ^{2} + 8}{( s + 2 ) ^{4}}

n = - 4 \sum \infty (- \frac{4}{11})^{n}

\frac{\partial}{\partial z} (x + z)

in v erse l a pl a ce \frac{2}{s \cdot ( s + 2 )}