What is the integral from-1 to 1 of x/(x^2+1) ?

The integral from-1 to 1 of x/(x^2+1) is 0

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integral from-1 to 1 of x/(x^2+1)

\int_{- 1}^{1} \frac{x}{x ^{2} + 1} d x

0

Solution steps

\int_{- 1}^{1} \frac{x}{x ^{2} + 1} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x}{x ^{2} + 1} :

Odd

= 0

\int 5 x^{\frac{2}{3}} d x

y = 6 x^{2} - x^{3}, (1, 5)

n = 0 \sum \infty \frac{1}{1 !}

\int 5^{x + 2} d x

\frac{d}{d x} ((x^{3} + 3)^{2})

What is the integral from-1 to 1 of x/(x^2+1) ?
The integral from-1 to 1 of x/(x^2+1) is 0