What is the derivative of (x^3+3^2) ?

The derivative of (x^3+3^2) is 6x^2(x^3+3)

What is the first derivative of (x^3+3^2) ?

The first derivative of (x^3+3^2) is 6x^2(x^3+3)

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\frac{d}{d x} ((x^{3} + 3)^{2})

6 x^{2} (x^{3} + 3)

Solution steps

\frac{d}{d x} ((x^{3} + 3)^{2})

Apply the chain rule:

2 (x^{3} + 3) \frac{d}{d x} (x^{3} + 3)

= 2 (x^{3} + 3) \frac{d}{d x} (x^{3} + 3)

\frac{d}{d x} (x^{3} + 3) = 3 x^{2}

= 2 (x^{3} + 3) \cdot 3 x^{2}

Simplify

= 6 x^{2} (x^{3} + 3)

(1, 3), (3, - 2)

\int - cos (t) - sin (t) d t

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\int \frac{x ^{4}}{7 - x ^{5}} d x

What is the derivative of (x^3+3^2) ?
The derivative of (x^3+3^2) is 6x^2(x^3+3)
What is the first derivative of (x^3+3^2) ?
The first derivative of (x^3+3^2) is 6x^2(x^3+3)