What is (\partial)/(\partial x)(3x^2y-4xy^2) ?

The answer to (\partial)/(\partial x)(3x^2y-4xy^2) is 6yx-4y^2

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(\partial)/(\partial x)(3x^2y-4xy^2)

\frac{\partial}{\partial x} (3 x^{2} y - 4 x y^{2})

6 y x - 4 y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{2} y - 4 x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2} y) - \frac{\partial}{\partial x} (4 x y^{2})

\frac{\partial}{\partial x} (3 x^{2} y) = 6 y x

\frac{\partial}{\partial x} (4 x y^{2}) = 4 y^{2}

= 6 y x - 4 y^{2}

\frac{t}{( t - 4 ) ^{2}}

f (x) = x^{2} - x, (3, 6)

a^{\frac{2}{3}}

6 x^{2}, x^{2} + 4

What is (\partial)/(\partial x)(3x^2y-4xy^2) ?
The answer to (\partial)/(\partial x)(3x^2y-4xy^2) is 6yx-4y^2