What is the tangent of f(x)=x^2-x,(3,6) ?

The tangent of f(x)=x^2-x,(3,6) is y=5x-9

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tangent of f(x)=x^2-x,(3,6)

tangent of

f (x) = x^{2} - x, (3, 6)

y = 5 x - 9

Solution steps

Find the slope of

f (x) = x^{2} - x : \frac{df ( x )}{d x} = 2 x - 1

Compute the slope of

f (x) = x^{2} - x

(3, 6) : m = 5

Find the line with slope m=

5

and passing through

(3, 6) : y = 5 x - 9

y = 5 x - 9

a^{\frac{2}{3}}

6 x^{2}, x^{2} + 4

\frac{\partial}{\partial x} (x^{2} - 3 y)

\frac{d y}{d x} = 1 - y

What is the tangent of f(x)=x^2-x,(3,6) ?
The tangent of f(x)=x^2-x,(3,6) is y=5x-9