What is the derivative of-(8x/((x^2-4)^2)) ?

The derivative of-(8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)

What is the first derivative of-(8x/((x^2-4)^2)) ?

The first derivative of-(8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- \frac{8 x}{( x ^{2} - 4 ) ^{2}})

- \frac{8 ( - 3 x ^{2} - 4 )}{( x ^{2} - 4 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{8 x}{( x ^{2} - 4 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (\frac{x}{( x ^{2} - 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 8 \cdot \frac{\frac{d x}{d x} ( x ^{2} - 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 4 ) ^{2} ) x}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} - 4)^{2}) = 4 x (x^{2} - 4)

= - 8 \cdot \frac{1 \cdot ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) x}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

Simplify

- 8 \cdot \frac{1 \cdot ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) x}{( ( x ^{2} - 4 ) ^{2} ) ^{2}} : - \frac{8 ( - 3 x ^{2} - 4 )}{( x ^{2} - 4 ) ^{3}}

= - \frac{8 ( - 3 x ^{2} - 4 )}{( x ^{2} - 4 ) ^{3}}

\int (cos (8 x) - csc^{2} (x)) d x

\frac{d}{d x} (x e^{s i n (x)})

n = 1 \sum \infty \frac{3 ^{n + 2}}{5 ^{n}}

(r^{5} - 4 r) e^{r}

\frac{d y}{d x} = (y^{2} - 9), y (1) = 4

What is the derivative of-(8x/((x^2-4)^2)) ?
The derivative of-(8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)
What is the first derivative of-(8x/((x^2-4)^2)) ?
The first derivative of-(8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)