What is the sum from n=1 to infinity}(3^{n+2 of)/(5^n) ?

The sum from n=1 to infinity}(3^{n+2 of)/(5^n) is converges

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sum from n=1 to infinity}(3^{n+2 of)/(5^n)

n = 1 \sum \infty \frac{3 ^{n + 2}}{5 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{3 ^{n + 2}}{5 ^{n}}

Apply Series Ratio Test:

converges

= converges

(r^{5} - 4 r) e^{r}

\frac{d y}{d x} = (y^{2} - 9), y (1) = 4

\int e^{x} cos (\frac{x}{2}) d x

\int \frac{2}{x ^{- 1} + 1} d x

\int \frac{4}{x ^{2} - 4 x + 9} d x

What is the sum from n=1 to infinity}(3^{n+2 of)/(5^n) ?
The sum from n=1 to infinity}(3^{n+2 of)/(5^n) is converges