What is the integral of 5sec^3(x) ?

The integral of 5sec^3(x) is 5(1/2 sec(x)tan(x)+1/2 ln|tan(x)+sec(x)|)+C

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integral of 5sec^3(x)

\int 5 sec^{3} (x) d x

5 (\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣) + C

Solution steps

\int 5 sec^{3} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int sec^{3} (x) d x

Apply Integral Reduction

= 5 (\frac{sec ^{2} ( x ) sin ( x )}{2} + \frac{1}{2} \cdot \int sec (x) d x)

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= 5 (\frac{sec ^{2} ( x ) sin ( x )}{2} + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣)

Simplify

5 (\frac{sec ^{2} ( x ) sin ( x )}{2} + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣) : 5 (\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣)

= 5 (\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣)

Add a constant to the solution

= 5 (\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣) + C

\frac{d}{d x} (e^{2 x} sin (2 x))

\frac{d}{d x} (\frac{( x )}{x + 1})

\frac{d}{d x} ((x^{2} + 1) e^{- x})

y = \frac{7 x - 3}{5 x + 4} + x^{3}

\int 8 e^{2 x} d x

What is the integral of 5sec^3(x) ?
The integral of 5sec^3(x) is 5(1/2 sec(x)tan(x)+1/2 ln|tan(x)+sec(x)|)+C