What is the derivative of 4x^3-3 ?

The derivative of 4x^3-3 is 12x^2

What is the first derivative of 4x^3-3 ?

The first derivative of 4x^3-3 is 12x^2

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\frac{d}{d x} (4 x^{3} - 3)

12 x^{2}

Solution steps

\frac{d}{d x} (4 x^{3} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (3) = 0

= 12 x^{2} - 0

Simplify

= 12 x^{2}

(e^{t} + e^{- t}) \frac{d x}{d t} = x^{2}

x^{2} y^{^{''}} + x y^{^{'}} + y = 0

\int 5 sec^{3} (x) d x

\frac{d}{d x} (e^{2 x} sin (2 x))

\frac{d}{d x} (\frac{( x )}{x + 1})

What is the derivative of 4x^3-3 ?
The derivative of 4x^3-3 is 12x^2
What is the first derivative of 4x^3-3 ?
The first derivative of 4x^3-3 is 12x^2