What is (\partial}{\partial x}(\frac{x+y)/2) ?

The answer to (\partial}{\partial x}(\frac{x+y)/2) is 1/2

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(\partial}{\partial x}(\frac{x+y)/2)

\frac{\partial}{\partial x} (\frac{x + y}{2})

\frac{1}{2}

Solution steps

\frac{\partial}{\partial x} (\frac{x + y}{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial x} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{2} (1 + 0)

Simplify

= \frac{1}{2}

\frac{3}{( s + 1 ) ^{2}}

n = 1 \sum \infty \frac{4 ^{n}}{2 ^{n}}

x y - 3 y^{2} = 8, (14, 4)

\int x e^{- x} d x

\frac{d}{d x} (\frac{2 x}{ln ( x )})

What is (\partial}{\partial x}(\frac{x+y)/2) ?
The answer to (\partial}{\partial x}(\frac{x+y)/2) is 1/2