What is (\partial)/(\partial x)(2x^3y+4) ?

The answer to (\partial)/(\partial x)(2x^3y+4) is 6x^2y

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(\partial)/(\partial x)(2x^3y+4)

\frac{\partial}{\partial x} (2 x^{3} y + 4)

6 x^{2} y

Solution steps

\frac{\partial}{\partial x} (2 x^{3} y + 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{3} y) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (2 x^{3} y) = 6 y x^{2}

\frac{\partial}{\partial x} (4) = 0

= 6 y x^{2} + 0

Simplify

= 6 x^{2} y

x \to 3 + lim (\frac{1}{x - 3})

\int_{- \infty}^{0} \frac{1}{5 - 3 x} d x

y^{^{'}} + y tan (t) = \frac{tan ( t )}{cos ( t )}

\int x^{3} I n (x) d x

e^{t} + 3, at t = 0

What is (\partial)/(\partial x)(2x^3y+4) ?
The answer to (\partial)/(\partial x)(2x^3y+4) is 6x^2y