What is the derivative of f(x)= 1/(5x+7) ?

The derivative of f(x)= 1/(5x+7) is -5/((5x+7)^2)

What is the first derivative of f(x)= 1/(5x+7) ?

The first derivative of f(x)= 1/(5x+7) is -5/((5x+7)^2)

derivative of

f (x) = \frac{1}{5 x + 7}

- \frac{5}{( 5 x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{5 x + 7})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((5 x + 7)^{- 1})

Apply the chain rule:

- \frac{1}{( 5 x + 7 ) ^{2}} \frac{d}{d x} (5 x + 7)

= - \frac{1}{( 5 x + 7 ) ^{2}} \frac{d}{d x} (5 x + 7)

\frac{d}{d x} (5 x + 7) = 5

= - \frac{1}{( 5 x + 7 ) ^{2}} \cdot 5

Simplify

- \frac{1}{( 5 x + 7 ) ^{2}} \cdot 5 : - \frac{5}{( 5 x + 7 ) ^{2}}

= - \frac{5}{( 5 x + 7 ) ^{2}}

t a y l or \frac{1}{( 1 + x )}

\frac{d}{d x} (3 x^{2} - 15)

n = 1 \sum \infty \frac{n}{n + 6}

x \to 0 lim ((1 - 6 x)^{\frac{2}{x}})

\int \frac{1}{x ^{11}} d x

What is the derivative of f(x)= 1/(5x+7) ?
The derivative of f(x)= 1/(5x+7) is -5/((5x+7)^2)
What is the first derivative of f(x)= 1/(5x+7) ?
The first derivative of f(x)= 1/(5x+7) is -5/((5x+7)^2)