What is the sum from n=1 to infinity of n/(n+6) ?

The sum from n=1 to infinity of n/(n+6) is diverges

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sum from n=1 to infinity of n/(n+6)

n = 1 \sum \infty \frac{n}{n + 6}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{n + 6}

Apply Series Divergence Test:

diverges

= diverges

x \to 0 lim ((1 - 6 x)^{\frac{2}{x}})

\int \frac{1}{x ^{11}} d x

x y^{2} (x \frac{d y}{d x} + y) = 9

x \to 5 + lim (ln (x - 5))

\frac{d}{d x} (\frac{2 ^{x}}{3 x - 1})

What is the sum from n=1 to infinity of n/(n+6) ?
The sum from n=1 to infinity of n/(n+6) is diverges