What is (\partial)/(\partial x)(x^3-6xy+y^3-2) ?

The answer to (\partial)/(\partial x)(x^3-6xy+y^3-2) is 3x^2-6y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^3-6xy+y^3-2)

\frac{\partial}{\partial x} (x^{3} - 6 x y + y^{3} - 2)

3 x^{2} - 6 y

Solution steps

\frac{\partial}{\partial x} (x^{3} - 6 x y + y^{3} - 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (6 x y) + \frac{\partial}{\partial x} (y^{3}) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (6 x y) = 6 y

\frac{\partial}{\partial x} (y^{3}) = 0

\frac{\partial}{\partial x} (2) = 0

= 3 x^{2} - 6 y + 0 - 0

Simplify

= 3 x^{2} - 6 y

\frac{d}{d t} (+ 6 t)

\int_{4}^{10} \frac{1}{36 + ( x - 4 ) ^{2}} d x

\frac{d}{d x} (9 + x)

\frac{1}{9 s ^{2} + 1}

What is (\partial)/(\partial x)(x^3-6xy+y^3-2) ?
The answer to (\partial)/(\partial x)(x^3-6xy+y^3-2) is 3x^2-6y