What is the integral of 1/(1+w^2) ?

The integral of 1/(1+w^2) is arctan(w)+C

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integral of 1/(1+w^2)

\int \frac{1}{1 + w ^{2}} d w

arctan (w) + C

Solution steps

\int \frac{1}{1 + w ^{2}} d w

Use the common integral:

\int \frac{1}{1 + w ^{2}} d w = arctan (w)

= arctan (w)

Add a constant to the solution

= arctan (w) + C

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