What is the limit as t approaches 0 of 9/t-9/(t^2+t) ?

The limit as t approaches 0 of 9/t-9/(t^2+t) is 9

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limit as t approaches 0 of 9/t-9/(t^2+t)

t \to 0 lim (\frac{9}{t} - \frac{9}{t ^{2} + t})

9

Solution steps

t \to 0 lim (\frac{9}{t} - \frac{9}{t ^{2} + t})

Simplify

\frac{9}{t} - \frac{9}{t ^{2} + t} : \frac{9}{t + 1}

= t \to 0 lim (\frac{9}{t + 1})

Plug in the value

t = 0

= \frac{9}{0 + 1}

Simplify

= 9

(y - x) y^{^{'}} = y - x + 3

\int \frac{1}{1 + w ^{2}} d w

\frac{d}{d x} (2 1 + x^{2} + 1)

x \to 3 lim (ln (x^{2} - 9))

\int \frac{5 x ^{2} + 20 x + 6}{x ( x + 1 ) ^{2}} d x

What is the limit as t approaches 0 of 9/t-9/(t^2+t) ?
The limit as t approaches 0 of 9/t-9/(t^2+t) is 9