What is (\partial)/(\partial z)(2xln(yz)) ?

The answer to (\partial)/(\partial z)(2xln(yz)) is (2x)/z

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(\partial)/(\partial z)(2xln(yz))

\frac{\partial}{\partial z} (2 x ln (yz))

\frac{2 x}{z}

Solution steps

\frac{\partial}{\partial z} (2 x ln (yz))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x \frac{\partial}{\partial z} (ln (yz))

Apply the chain rule:

\frac{1}{yz} \frac{\partial}{\partial z} (yz)

= \frac{1}{yz} \frac{\partial}{\partial z} (yz)

\frac{\partial}{\partial z} (yz) = y

= 2 x \frac{1}{yz} y

Simplify

2 x \frac{1}{yz} y : \frac{2 x}{z}

= \frac{2 x}{z}

\frac{d}{d y} (sin (y^{2}))

\frac{\partial}{\partial x} (n ln (θ + 2))

\int x^{2} - 3 d x

f (x) = \frac{x}{1 + x ^{2}}, 0, at x = 0

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + 7)

What is (\partial)/(\partial z)(2xln(yz)) ?
The answer to (\partial)/(\partial z)(2xln(yz)) is (2x)/z