What is the integral of sin(x^4) ?

The integral of sin(x^4) is 1/8 ix(\E_{3/4}(-ix^4)-\E_{3/4}(ix^4))+C

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integral of sin(x^4)

\int sin (x^{4}) d x

\frac{1}{8} i x (E_{\frac{3}{4}} (- i x^{4}) - E_{\frac{3}{4}} (i x^{4})) + C

Solution steps

\int sin (x^{4}) d x

Use the nonelementary integral:

\int sin (x^{4}) d x = \frac{1}{8} i x (E_{\frac{3}{4}} (- i x^{4}) - E_{\frac{3}{4}} (i x^{4}))

= \frac{1}{8} i x (E_{\frac{3}{4}} (- i x^{4}) - E_{\frac{3}{4}} (i x^{4}))

Add a constant to the solution

= \frac{1}{8} i x (E_{\frac{3}{4}} (- i x^{4}) - E_{\frac{3}{4}} (i x^{4})) + C

\frac{\partial}{\partial z} (2 x ln (yz))

\frac{d}{d y} (sin (y^{2}))

\frac{\partial}{\partial x} (n ln (θ + 2))

\int x^{2} - 3 d x

f (x) = \frac{x}{1 + x ^{2}}, 0, at x = 0

What is the integral of sin(x^4) ?
The integral of sin(x^4) is 1/8 ix(\E_{3/4}(-ix^4)-\E_{3/4}(ix^4))+C