What is the solution for (-4x+3y-7)dx-(x+1)dy=0 ?

The solution for (-4x+3y-7)dx-(x+1)dy=0 is y=c_{1}x^3+3c_{1}x^2+2x+3c_{1}x+c_{1}+3

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(-4x+3y-7)dx-(x+1)dy=0

(- 4 x + 3 y - 7) d x - (x + 1) d y = 0

y = c_{1} x^{3} + 3 c_{1} x^{2} + 2 x + 3 c_{1} x + c_{1} + 3

Solution steps

(- 4 x + 3 y - 7) d x - (x + 1) d y = 0

Solve linear ODE:

y = c_{1} x^{3} + 3 c_{1} x^{2} + 2 x + 3 c_{1} x + c_{1} + 3

y = c_{1} x^{3} + 3 c_{1} x^{2} + 2 x + 3 c_{1} x + c_{1} + 3

\frac{\partial}{\partial x} (x + x y^{2})

\int \frac{1}{sin ( x )} \frac{cos ( x )}{sin ( x )} d x

h \to 0 lim (\frac{( 1 + h ) 3 - 1}{h})

x, y \to (0, 0) lim (\frac{( 2 x ^{2} y )}{x ^{2} + y ^{4}})

x \to 2 + lim (3 - x)

What is the solution for (-4x+3y-7)dx-(x+1)dy=0 ?
The solution for (-4x+3y-7)dx-(x+1)dy=0 is y=c_{1}x^3+3c_{1}x^2+2x+3c_{1}x+c_{1}+3