What is the limit as h approaches 0 of ((1+h)3-1)/h ?

The limit as h approaches 0 of ((1+h)3-1)/h is diverges

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limit as h approaches 0 of ((1+h)3-1)/h

h \to 0 lim (\frac{( 1 + h ) 3 - 1}{h})

diverges

Solution steps

h \to 0 lim (\frac{( 1 + h ) \cdot 3 - 1}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{( 1 + h ) \cdot 3 - 1}{h}) = \infty

h \to 0 - lim (\frac{( 1 + h ) \cdot 3 - 1}{h}) = - \infty

= diverges

x, y \to (0, 0) lim (\frac{( 2 x ^{2} y )}{x ^{2} + y ^{4}})

x \to 2 + lim (3 - x)

\frac{d}{d x} (\frac{2 ^{x}}{cos ( x )})

y^{^{''}} + 2 y^{^{'}} + y = 64 e^{(7 t)}

\frac{d}{d x} ((x - 3)^{- 2})

What is the limit as h approaches 0 of ((1+h)3-1)/h ?
The limit as h approaches 0 of ((1+h)3-1)/h is diverges