{
"query": {
"display": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(2\\sqrt{x\\cdot\\:y}-\\frac{1}{2}x^{2}\\right)$$",
"symbolab_question": "DERIVATIVE#\\frac{\\partial }{\\partial x}(2\\sqrt{x\\cdot y}-\\frac{1}{2}x^{2})"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Partial Derivatives",
"default": "\\sqrt{\\frac{y}{x}}-x",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(2\\sqrt{xy}-\\frac{1}{2}x^{2}\\right)=\\sqrt{\\frac{y}{x}}-x$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(2\\sqrt{xy}-\\frac{1}{2}x^{2}\\right)",
"steps": [
{
"type": "interim",
"title": "Simplify $$2\\sqrt{xy}-\\frac{1}{2}x^{2}:{\\quad}2\\sqrt{xy}-\\frac{x^{2}}{2}$$",
"input": "2\\sqrt{xy}-\\frac{1}{2}x^{2}",
"steps": [
{
"type": "interim",
"title": "$$\\frac{1}{2}x^{2}=\\frac{x^{2}}{2}$$",
"input": "\\frac{1}{2}x^{2}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:x^{2}}{2}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:x^{2}=x^{2}$$",
"result": "=\\frac{x^{2}}{2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79noABpxc4IZFb3O0CFaPASdVBn2NNCFZqg4ZoVh6UwqjkVi15I8rBefLi4Iyt2wrqh2FHwNgeYX+xRFflBDUAT/L0MoYg+CUn6oyL3EO7Yp+kTAQ0wijjZT3CzKzoPHUjWa5dKN7qgdYIdTn58c30Y8BPOx0wlsgFN8qUa6AzA0="
}
},
{
"type": "step",
"result": "=2\\sqrt{xy}-\\frac{x^{2}}{2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{\\partial\\:}{\\partial\\:x}\\left(2\\sqrt{xy}-\\frac{x^{2}}{2}\\right)"
},
{
"type": "step",
"primary": "Treat $$y\\:$$as a constant"
},
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{\\partial\\:}{\\partial\\:x}\\left(2\\sqrt{xy}\\right)-\\frac{\\partial\\:}{\\partial\\:x}\\left(\\frac{x^{2}}{2}\\right)"
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(2\\sqrt{xy}\\right)=\\sqrt{\\frac{y}{x}}$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(2\\sqrt{xy}\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=2\\frac{\\partial\\:}{\\partial\\:x}\\left(\\sqrt{xy}\\right)"
},
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}\\frac{1}{2\\sqrt{xy}}\\frac{\\partial\\:}{\\partial\\:x}\\left(xy\\right)$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(\\sqrt{xy}\\right)",
"result": "=\\frac{1}{2\\sqrt{xy}}\\frac{\\partial\\:}{\\partial\\:x}\\left(xy\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=\\sqrt{u},\\:\\:u=xy$$"
],
"result": "=\\frac{\\partial\\:}{\\partial\\:u}\\left(\\sqrt{u}\\right)\\frac{\\partial\\:}{\\partial\\:x}\\left(xy\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:u}\\left(\\sqrt{u}\\right)=\\frac{1}{2\\sqrt{u}}$$",
"input": "\\frac{\\partial\\:}{\\partial\\:u}\\left(\\sqrt{u}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}=a^{\\frac{1}{2}}$$",
"result": "=\\frac{\\partial\\:}{\\partial\\:u}\\left(u^{\\frac{1}{2}}\\right)",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=\\frac{1}{2}u^{\\frac{1}{2}-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{1}{2}u^{\\frac{1}{2}-1}:{\\quad}\\frac{1}{2\\sqrt{u}}$$",
"input": "\\frac{1}{2}u^{\\frac{1}{2}-1}",
"result": "=\\frac{1}{2\\sqrt{u}}",
"steps": [
{
"type": "interim",
"title": "$$u^{\\frac{1}{2}-1}=u^{-\\frac{1}{2}}$$",
"input": "u^{\\frac{1}{2}-1}",
"steps": [
{
"type": "interim",
"title": "Join $$\\frac{1}{2}-1:{\\quad}-\\frac{1}{2}$$",
"input": "\\frac{1}{2}-1",
"result": "=u^{-\\frac{1}{2}}",
"steps": [
{
"type": "step",
"primary": "Convert element to fraction: $$1=\\frac{1\\cdot\\:2}{2}$$",
"result": "=-\\frac{1\\cdot\\:2}{2}+\\frac{1}{2}"
},
{
"type": "step",
"primary": "Since the denominators are equal, combine the fractions: $$\\frac{a}{c}\\pm\\frac{b}{c}=\\frac{a\\pm\\:b}{c}$$",
"result": "=\\frac{-1\\cdot\\:2+1}{2}"
},
{
"type": "interim",
"title": "$$-1\\cdot\\:2+1=-1$$",
"input": "-1\\cdot\\:2+1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:2=2$$",
"result": "=-2+1"
},
{
"type": "step",
"primary": "Add/Subtract the numbers: $$-2+1=-1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s731snK5z/nd3Sq/6JpCqiX1XTSum/z5kLpMzXS1UJIew02FKSBoQo9V3G05AlnWtTyCE30rzMlUAIVDyhseMBropKGn5MuXZnb2ZCo/hVsBU="
}
},
{
"type": "step",
"result": "=\\frac{-1}{2}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{1}{2}"
}
],
"meta": {
"interimType": "Algebraic Manipulation Join Concise Title 1Eq"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7VcI2MpaClJgyGWg1EkySKe0se7vRyav6BwUCJZptwG3MwViaLUXkeD+JukROhWdjMvOxDqXzE3/CFO0TFmffHAH2kDe5DGYTz3TrPquGdIhyukSOA/1RgMKO0TMhInPOMabdUggEogUL9RT7PNKh0VQW3Chm7McvYpuS87Y5EFs="
}
},
{
"type": "step",
"result": "=\\frac{1}{2}u^{-\\frac{1}{2}}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$a^{-b}=\\frac{1}{a^b}$$",
"secondary": [
"$$u^{-\\frac{1}{2}}=\\frac{1}{\\sqrt{u}}$$"
],
"result": "=\\frac{1}{2}\\cdot\\:\\frac{1}{\\sqrt{u}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=\\frac{1\\cdot\\:1}{2\\sqrt{u}}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:1=1$$",
"result": "=\\frac{1}{2\\sqrt{u}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7JOPQ2g2GS9EQptV8nckZSrH6E/qPf7AlxQDX8MXU5OsAlilG71elit3w1IBbYN0P8rEus7TgCihQBF5omOFkJv2RkT96g5Q5jVbn5fyeQzwB9pA3uQxmE8906z6rhnSIHimBRYRqHSWeJkuUPhfTC1O468YRFxaQeTFqgRqR2rvsVWktCxa7XSYzIK90x3+aTk5AXTHU+C+TrGKWzqT97A=="
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{1}{2\\sqrt{u}}\\frac{\\partial\\:}{\\partial\\:x}\\left(xy\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=xy$$",
"result": "=\\frac{1}{2\\sqrt{xy}}\\frac{\\partial\\:}{\\partial\\:x}\\left(xy\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAm8pe5pZooY9F76lMXc+eW7hUG3ehOs1lVTUNFnEOFcstTaRI+MlBUxEaHqiUUS2BwT4mfudsQdl9XEOhHRuSEDhCJTF6MA1EfdSpf0hOXKBWRI6gtQV6C3py6o6agV4be2CNnwanyZsA0WsLyuo+purhXHi/NHF/lcJBH8m03Z+YEfd615wJbmsw+mfnotEc9SBv6izheLVUKQ/emokAUymtoIVIiI8N9ZX5PJNj61yLCI2sSeA74029n2yo277ZU="
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(xy\\right)=y$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(xy\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=y\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)=1$$",
"result": "=y\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=y",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAkCHrPsxDHNAfe2TPFce/rinFjOV6V4e2DrBKqW1EhFu5KCf/kU7OLqVO3RHXJ9Wv0OG38IleojCyebAtZy+3Tm9JiwEB0ZXmaMqMWNNpbCrjG1uBlSxEBevFU4pf3SPbWwiNrEngO+NNvZ9sqNu+2V"
}
},
{
"type": "step",
"result": "=2\\cdot\\:\\frac{1}{2\\sqrt{xy}}y"
},
{
"type": "interim",
"title": "Simplify $$2\\cdot\\:\\frac{1}{2\\sqrt{xy}}y:{\\quad}\\sqrt{\\frac{y}{x}}$$",
"input": "2\\cdot\\:\\frac{1}{2\\sqrt{xy}}y",
"result": "=\\sqrt{\\frac{y}{x}}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2y}{2\\sqrt{xy}}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=\\frac{1\\cdot\\:y}{\\sqrt{xy}}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:y=y$$",
"result": "=\\frac{y}{\\sqrt{yx}}"
},
{
"type": "interim",
"title": "Factor $$\\sqrt{yx}:{\\quad}\\sqrt{y}\\sqrt{x}$$",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{ab}=\\sqrt[n]{a}\\sqrt[n]{b}$$",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"result": "=\\sqrt{y}\\sqrt{x}"
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{y}{\\sqrt{y}\\sqrt{x}}"
},
{
"type": "interim",
"title": "Cancel $$\\frac{y}{\\sqrt{x}\\sqrt{y}}:{\\quad}\\frac{\\sqrt{y}}{\\sqrt{x}}$$",
"input": "\\frac{y}{\\sqrt{x}\\sqrt{y}}",
"result": "=\\frac{\\sqrt{y}}{\\sqrt{x}}",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a}=a^{\\frac{1}{n}}$$",
"secondary": [
"$$\\sqrt{y}=y^{\\frac{1}{2}}$$"
],
"result": "=\\frac{y}{y^{\\frac{1}{2}}\\sqrt{x}}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\frac{x^{a}}{x^{b}}=x^{a-b}$$",
"secondary": [
"$$\\frac{y^{1}}{y^{\\frac{1}{2}}}=y^{1-\\frac{1}{2}}$$"
],
"result": "=\\frac{y^{1-\\frac{1}{2}}}{\\sqrt{x}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Subtract the numbers: $$1-\\frac{1}{2}=\\frac{1}{2}$$",
"result": "=\\frac{y^{\\frac{1}{2}}}{\\sqrt{x}}"
},
{
"type": "step",
"primary": "Apply radical rule: $$a^{\\frac{1}{n}}=\\sqrt[n]{a}$$",
"secondary": [
"$$y^{\\frac{1}{2}}=\\sqrt{y}$$"
],
"result": "=\\frac{\\sqrt{y}}{\\sqrt{x}}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
}
],
"meta": {
"interimType": "Generic Cancel Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYjEP/+4rMmkKtXP0lOp7OSFKUDIohh31lRymt/QFLzzNCUCWbkwGOY7PqKo3U/JLJegT4HcZpSp1R2uDAGeKel5ecH99gJxrutAMqpNKf6LMo3oe/oyhMy2+1TQhDBd2f5CDbprbpsc66sdPy4iJzM9O3DnP75oWhpA2FStW0p16xbo02WPWFMMXxAmyL6zOIw=="
}
},
{
"type": "step",
"primary": "Combine same powers : $$\\frac{\\sqrt{x}}{\\sqrt{y}}=\\sqrt{\\frac{x}{y}}$$",
"result": "=\\sqrt{\\frac{y}{x}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7/OsC643lXZbU+VEjF1qvimRI6gtQV6C3py6o6agV4bdLEExALrl6PWSpc3fDbWRbQslTDKxOR/6J+ZOGvUcaui8GzCD1T8ndxnMSCPgnUJAB9pA3uQxmE8906z6rhnSIHimBRYRqHSWeJkuUPhfTC60l0D77ht0SUAIhkGN1+oC0/h1b/xhPxfsYnYXov3MvMgmFidzLn8qAVzHC0VZJUA=="
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(\\frac{x^{2}}{2}\\right)=x$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(\\frac{x^{2}}{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=\\frac{1}{2}\\frac{\\partial\\:}{\\partial\\:x}\\left(x^{2}\\right)"
},
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=\\frac{1}{2}\\cdot\\:2x^{2-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{1}{2}\\cdot\\:2x^{2-1}:{\\quad}x$$",
"input": "\\frac{1}{2}\\cdot\\:2x^{2-1}",
"result": "=x",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2x^{2-1}}{2}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=1\\cdot\\:x^{2-1}"
},
{
"type": "interim",
"title": "$$x^{2-1}=x$$",
"input": "x^{2-1}",
"steps": [
{
"type": "step",
"primary": "Subtract the numbers: $$2-1=1$$",
"result": "=x^{1}"
},
{
"type": "step",
"primary": "Apply rule $$a^{1}=a$$",
"result": "=x"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
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}
},
{
"type": "step",
"result": "=1\\cdot\\:x"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:x=x$$",
"result": "=x"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l3vTdf410Ywhq1vZ0kzF8RYahDgkU0qhrtp0v+o3QgzehkKrn0era9rz8TlL+x/vjFJYCq5U0+2hzbvgLJypfoEFMST8lDZxn1Yq5HMKVTtAb51BceE+a5ppiVMbLOTZm0OUp9nwmzb09ceQZ5nHJLqPFeMAv2RMLBzqY1FeCKw="
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\sqrt{\\frac{y}{x}}-x"
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Partial%20Derivatives",
"practiceTopic": "Partial Derivatives"
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Simplify
Treat as a constant
Apply the Sum/Difference Rule:
Popular Examples
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Frequently Asked Questions (FAQ)
What is (\partial)/(\partial x)(2sqrt(x*y)-1/2 x^2) ?
The answer to (\partial)/(\partial x)(2sqrt(x*y)-1/2 x^2) is sqrt(y/x)-x