{
"query": {
"display": "$$\\int\\:\\frac{1}{\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)}dx$$",
"symbolab_question": "BIG_OPERATOR#\\int \\frac{1}{\\cos(x)\\sin(x)+\\cos^{2}(x)}dx"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Integrals",
"subTopic": "Indefinite Integrals",
"default": "\\frac{1}{2}\\ln\\left|1-\\tan^{2}(x)\\right|+\\frac{1}{2}\\ln\\left|\\tan(2x)+\\sec(2x)\\right|+C",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\int\\:\\frac{1}{\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)}dx=\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|+\\frac{1}{2}\\ln\\left|\\tan\\left(2x\\right)+\\sec\\left(2x\\right)\\right|+C$$",
"input": "\\int\\:\\frac{1}{\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)}dx",
"steps": [
{
"type": "interim",
"title": "Multiply by the conjugate of $$\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right):\\:\\frac{-\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}$$",
"input": "\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)",
"result": "=\\int\\:\\frac{1}{\\frac{-\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}}dx",
"steps": [
{
"type": "step",
"primary": "Multiply by the conjugate $$\\frac{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}$$",
"result": "=\\frac{\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)\\right)\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}"
},
{
"type": "interim",
"title": "Expand $$\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)\\right)\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)\\right):{\\quad}-\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)$$",
"input": "\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)\\right)\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "$$\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)=-\\cos\\left(2x\\right)$$",
"input": "\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "Expand $$\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right):{\\quad}\\sin^{2}\\left(x\\right)-\\cos^{2}\\left(x\\right)$$",
"input": "\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)",
"result": "=\\sin^{2}\\left(x\\right)-\\cos^{2}\\left(x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply Difference of Two Squares Formula: $$\\left(a+b\\right)\\left(a-b\\right)=a^{2}-b^{2}$$",
"secondary": [
"$$a=\\sin\\left(x\\right),\\:b=\\cos\\left(x\\right)$$"
],
"result": "=\\sin^{2}\\left(x\\right)-\\cos^{2}\\left(x\\right)",
"meta": {
"practiceLink": "/practice/expansion-practice#area=main&subtopic=Difference%20of%20Two%20Squares",
"practiceTopic": "Expand Difference of Squares"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Expand Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7cC2vx16a275Ce2/7HPHNaJpLRyyHUTF4keWRdUZ3nU8K8N1AvD/sjs+O3GJ0pZVBdYPfXQvX4/bINBB8wSEQ0TCZemGhnJ26dWCehvTfL5nHINhZ9+q4VDfZQA2foKJ7o3oe/oyhMy2+1TQhDBd2f4XZazvhtEMhdr5iLwjMPT6nrQ95xJxb0/iBFlfol3Uz4W0t+3k+sFrKUXIXwoCVSLsYMOfMWJINjcdqbrjG2Fk="
}
},
{
"type": "step",
"primary": "Use the Double Angle identity: $$\\cos^{2}\\left(x\\right)-\\sin^{2}\\left(x\\right)=\\cos\\left(2x\\right)$$",
"secondary": [
"$$-\\cos^{2}\\left(x\\right)+\\sin^{2}\\left(x\\right)=-\\cos\\left(2x\\right)$$"
],
"result": "=-\\cos\\left(2x\\right)"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"result": "=\\cos^{2}\\left(x\\right)\\left(-\\cos\\left(2x\\right)\\right)"
},
{
"type": "interim",
"title": "Factor $$\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)\\right)\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)\\right):{\\quad}\\cos^{2}\\left(x\\right)\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)$$",
"input": "\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)\\right)\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)\\right)",
"result": "=\\cos^{2}\\left(x\\right)\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "Factor $$\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right):{\\quad}\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)$$",
"input": "\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos^{2}\\left(x\\right)",
"result": "=\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^{b}a^{c}$$",
"secondary": [
"$$\\cos^{2}\\left(x\\right)=\\cos\\left(x\\right)\\cos\\left(x\\right)$$"
],
"result": "=\\cos\\left(x\\right)\\sin\\left(x\\right)+\\cos\\left(x\\right)\\cos\\left(x\\right)",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Factor out common term $$\\cos\\left(x\\right)$$",
"result": "=\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "interim",
"title": "Factor $$\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right):{\\quad}\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)$$",
"input": "\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)",
"result": "=\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^{b}a^{c}$$",
"secondary": [
"$$\\cos^{2}\\left(x\\right)=\\cos\\left(x\\right)\\cos\\left(x\\right)$$"
],
"result": "=\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos\\left(x\\right)\\cos\\left(x\\right)",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Factor out common term $$\\cos\\left(x\\right)$$",
"result": "=\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"primary": "Refine",
"result": "=\\cos^{2}\\left(x\\right)\\left(\\sin\\left(x\\right)+\\cos\\left(x\\right)\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)"
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"result": "=-\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Expand Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s761C1I6HckjQ8wB9k8UNnejsXyd2ntXQlEAn8lwjgVzgpg2QlDXoBFDV8czBR0YeoMERZVLxN/Lg/eKiKCvsIFwCWKUbvV6WK3fDUgFtg3Q+Vu0y/nymFFvapFvN0D5+8cs7YyTnmUlHIXdyPqusBGvrIewIbgQd8+Nk4C+T0LHbe1A9ekahUIWtvNWrN4v94WJ7MAlyIlOhhjL1gSUtFjJp0GdLahlxcloLqWlCBNWSdwn6QklnfOj/iz73NvkbakFLb2Q7540VQhS6ZjLkSc7ZkYtBN3gtB3v8REqVC4VY="
}
},
{
"type": "step",
"result": "=\\frac{-\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}"
}
],
"meta": {
"interimType": "Multiply Divide Conjugate 2Eq"
}
},
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=-\\int\\:\\frac{1}{\\frac{\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}}dx"
},
{
"type": "interim",
"title": "Expand $$\\frac{1}{\\frac{\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}}:{\\quad}\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}-\\frac{1}{\\cos\\left(2x\\right)}$$",
"input": "\\frac{1}{\\frac{\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{1}{\\frac{b}{c}}=\\frac{c}{b}$$",
"result": "=\\frac{\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)}{\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}"
},
{
"type": "interim",
"title": "Factor $$\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right):{\\quad}\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)$$",
"input": "\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos^{2}\\left(x\\right)",
"result": "=\\frac{\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)}{\\cos^{2}\\left(x\\right)\\cos\\left(2x\\right)}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^{b}a^{c}$$",
"secondary": [
"$$\\cos^{2}\\left(x\\right)=\\cos\\left(x\\right)\\cos\\left(x\\right)$$"
],
"result": "=\\cos\\left(x\\right)\\sin\\left(x\\right)-\\cos\\left(x\\right)\\cos\\left(x\\right)",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Factor out common term $$\\cos\\left(x\\right)$$",
"result": "=\\cos\\left(x\\right)\\left(\\sin\\left(x\\right)-\\cos\\left(x\\right)\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"primary": "Cancel the common factor: $$\\cos\\left(x\\right)$$",
"result": "=\\frac{\\sin\\left(x\\right)-\\cos\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{a\\pm\\:b}{c}=\\frac{a}{c}\\pm\\:\\frac{b}{c}$$",
"secondary": [
"$$\\frac{\\sin\\left(x\\right)-\\cos\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}=\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}-\\frac{\\cos\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}$$"
],
"result": "=\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}-\\frac{\\cos\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}"
},
{
"type": "interim",
"title": "Cancel $$\\frac{\\cos\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}:{\\quad}\\frac{1}{\\cos\\left(2x\\right)}$$",
"input": "\\frac{\\cos\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}",
"steps": [
{
"type": "step",
"primary": "Cancel the common factor: $$\\cos\\left(x\\right)$$",
"result": "=\\frac{1}{\\cos\\left(2x\\right)}"
}
],
"meta": {
"interimType": "Generic Cancel Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYqY5ewE651e6m6D/ouNDQVC72U4SBMbmhmIphc/RtKoS3oZCq59Hq2va8/E5S/sf72Sa96ofM+5vPZoutcj6hmh92pSYNEMr9NFedeYhwYIb72wZm7kDUxdE6YSmfEbr2rA6UckXd5QhYMrrQC3e3Ib5PwvM7XKO3kL37Krbg4WN1ipklNwAYI3aqjqzKv7YArCI2sSeA74029n2yo277ZU="
}
},
{
"type": "step",
"result": "=\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}-\\frac{1}{\\cos\\left(2x\\right)}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Expand Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7nIyYUEjnwJO2hdBXNY/0co5XWCHPnyowIRNxqOR/NagycU28KAypNFvulkZhr333ofc85/oqy+yrbKtPyZ7PxUScXOS1iqwYhVyufRVfjd4DnzlbPZjyKgy1eUCFsLd59wUEHG2dTu2P2I+pIwlgwQVaH5VZwoTIHoZC5x/vXOo2f8rRAs4eOHhzsWZxtU+xhAoJoo+JbeTbUUsvSlAd7qN6Hv6MoTMtvtU0IQwXdn9PNSm+B7nW4/+8BgmEMMqr0Ynw7bx9xwgHh4VzF6hbxPPtUlbpXhZx4K8ZmqInRzOUNMAWK+azJYxoRUhclqtcELKzkfRLwhqzh627QQuMkbMukdvk8d8PpMtD+3DXp74="
}
},
{
"type": "step",
"result": "=-\\int\\:\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}-\\frac{1}{\\cos\\left(2x\\right)}dx"
},
{
"type": "step",
"primary": "Apply the Sum Rule: $$\\int{f\\left(x\\right){\\pm}g\\left(x\\right)}dx=\\int{f\\left(x\\right)}dx{\\pm}\\int{g\\left(x\\right)}dx$$",
"result": "=-\\left(\\int\\:\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}dx-\\int\\:\\frac{1}{\\cos\\left(2x\\right)}dx\\right)"
},
{
"type": "interim",
"title": "$$\\int\\:\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}dx=-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|$$",
"input": "\\int\\:\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)\\cos\\left(2x\\right)}dx",
"steps": [
{
"type": "step",
"primary": "Use the basic trigonometric identity: $$\\frac{\\sin\\left(x\\right)}{\\cos\\left(x\\right)}=\\tan\\left(x\\right)$$",
"result": "=\\int\\:\\frac{\\tan\\left(x\\right)}{\\cos\\left(2x\\right)}dx"
},
{
"type": "interim",
"title": "Apply u-substitution",
"input": "\\int\\:\\frac{\\tan\\left(x\\right)}{\\cos\\left(2x\\right)}dx",
"steps": [
{
"type": "definition",
"title": "Integral Substitution definition",
"text": "$$\\int\\:f\\left(g\\left(x\\right)\\right)\\cdot\\:g'\\left(x\\right)dx=\\int\\:f\\left(u\\right)du,\\:\\quad\\:u=g\\left(x\\right)$$",
"secondary": [
"Substitute: $$u=2x$$"
]
},
{
"type": "interim",
"title": "$$\\frac{du}{dx}=2$$",
"input": "\\frac{d}{dx}\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=2\\frac{dx}{dx}"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=2\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=2",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYg2sQzwGEAAPyDk8n13Ps8XZGku9zFkxwe1dTH8vycb94wHsFp27x8BxzSfXYcuPllNbbqpyK7JQEZdATEJR51iZ4v02Fm2dNqQJZnxCX4Je"
}
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:du=2dx$$"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:dx=\\frac{1}{2}du$$"
},
{
"type": "step",
"result": "=\\int\\:\\frac{\\tan\\left(x\\right)}{\\cos\\left(u\\right)}\\cdot\\:\\frac{1}{2}du"
},
{
"type": "interim",
"title": "Simplify $$\\frac{\\tan\\left(x\\right)}{\\cos\\left(u\\right)}\\cdot\\:\\frac{1}{2}:{\\quad}\\frac{\\tan\\left(x\\right)}{2\\cos\\left(u\\right)}$$",
"input": "\\frac{\\tan\\left(x\\right)}{\\cos\\left(u\\right)}\\cdot\\:\\frac{1}{2}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=\\frac{\\tan\\left(x\\right)\\cdot\\:1}{\\cos\\left(u\\right)\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply: $$\\tan\\left(x\\right)\\cdot\\:1=\\tan\\left(x\\right)$$",
"result": "=\\frac{\\tan\\left(x\\right)}{2\\cos\\left(u\\right)}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{\\tan\\left(x\\right)}{2\\cos\\left(u\\right)}du"
},
{
"type": "interim",
"title": "$$u=2x\\quad\\Rightarrow\\quad\\:x=\\frac{u}{2}$$",
"input": "2x=u",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2x=u",
"result": "x=\\frac{u}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2x}{2}=\\frac{u}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "x=\\frac{u}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7s0YJ9dJv5Dl8F7mDCbfsDnqmU5rQtJ8zdtqJ0kjhpCmAihI8YpOa7YjcZorvECwsGTs6/dv6vqGrZei/KKb0d86/VqkoPQqifJZOXxDrBkMKA/ZpOZ/69yR+tuSn6BgZ0hYzF6vxjSZoMSInCY/PPQbO95/2yiZOrh8Vdx/OHPuFQ3UuMN2HjfLo8oa2XvK6BDwaRpaOYMYJ5alxu/Tk7SsQJI3XYN53WJRH4w1fBaw5jJ+yLqEykw3r/NtwCEx8fWNxKyXHwwVu3B/zVqphFYy9A+rBHtGNivzunox1gJf7NVgNvfd+I+ThtEYuVt+OIZ3rul4ahYOQTdajruA+FlfD3lgdqWCNo0B+BzwNiddiIHEQdKO874QnGiEBZuQkxBVMhfEdue6qsYh7lS/4QsMhSOmsID5cim3F9v8Rs44HgIRL2cbEPZLm634cOSI7G1YrInBT7eibt4cYhvHwDzRQJEdnJEoPNB8oHGc09FO8leuFFBMpmtXRConWh4AZ+97UWQsZjLul80dbuB7w9a1I6yWflsFlt3bztcKjbqc6SvZ4Z3EOq8xsbPTUoN8oSFT6P+KXHRsnmtqFaQvN/Q=="
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{\\tan\\left(\\frac{u}{2}\\right)}{2\\cos\\left(u\\right)}du"
}
],
"meta": {
"interimType": "Integral U Substitution 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s71lewa+fm1gllISKpm3bbq0rZ3wSZocwjtUDIp+GK4jPSUM9pakkKILvT6Fs/PM35zdOFr14NhlnTuLeZXt0DnkvTqyge4+vpHW4VBaWAsV8Eoy0xTg26MoOt6jFtKKexmeVl3Sr6Lsj1TDP8q1VHm0/kIufF9OwaAuPjf2I6SDjZEt3ZXAiqUE0HIXrrrezJAIOLq+Zo6QPUdsELPTSSFYFODKn911wSXXfeQ1ST5CA"
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{\\tan\\left(\\frac{u}{2}\\right)}{2\\cos\\left(u\\right)}du"
},
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=\\frac{1}{2}\\cdot\\:\\int\\:\\frac{\\tan\\left(\\frac{u}{2}\\right)}{\\cos\\left(u\\right)}du"
},
{
"type": "interim",
"title": "Apply u-substitution",
"input": "\\int\\:\\frac{\\tan\\left(\\frac{u}{2}\\right)}{\\cos\\left(u\\right)}du",
"steps": [
{
"type": "definition",
"title": "Integral Substitution definition",
"text": "$$\\int\\:f\\left(g\\left(x\\right)\\right)\\cdot\\:g'\\left(x\\right)dx=\\int\\:f\\left(u\\right)du,\\:\\quad\\:u=g\\left(x\\right)$$",
"secondary": [
"Substitute: $$v=\\tan\\left(\\frac{u}{2}\\right)$$"
]
},
{
"type": "step",
"primary": "Using Weierstrass Substitution:"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:\\cos\\left(u\\right)=\\frac{1-v^{2}}{1+v^{2}},\\:\\tan\\left(\\frac{u}{2}\\right)=v$$"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:du=\\frac{2}{1+v^{2}}dv$$"
},
{
"type": "step",
"result": "=\\int\\:\\frac{v}{\\frac{1-v^{2}}{1+v^{2}}}\\cdot\\:\\frac{2}{1+v^{2}}dv"
},
{
"type": "interim",
"title": "Simplify $$\\frac{v}{\\frac{1-v^{2}}{1+v^{2}}}\\cdot\\:\\frac{2}{1+v^{2}}:{\\quad}\\frac{2v}{1-v^{2}}$$",
"input": "\\frac{v}{\\frac{1-v^{2}}{1+v^{2}}}\\cdot\\:\\frac{2}{1+v^{2}}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{a}{\\frac{b}{c}}=\\frac{a\\cdot\\:c}{b}$$",
"result": "=\\frac{v\\left(v^{2}+1\\right)}{-v^{2}+1}\\cdot\\:\\frac{2}{v^{2}+1}"
},
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=\\frac{v\\left(1+v^{2}\\right)\\cdot\\:2}{\\left(1-v^{2}\\right)\\left(1+v^{2}\\right)}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$1+v^{2}$$",
"result": "=\\frac{v\\cdot\\:2}{1-v^{2}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{2v}{1-v^{2}}dv"
}
],
"meta": {
"interimType": "Integral U Substitution 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s7xKTxOnyP2m1trLSF0ERscEQ5lfIU08cV7QYC/RfTanleL0LXjSZHEeyHU5TcRN7QVQS/Jt0lGNpQG/dCOLjzQekCgntDFdUQWCp8pL+1z0BPbm+EfPW2lf+ZDdfktozvWSzo9f74o6ikYmbvxINF4Us/9CZe3M0pPx3HG5wYcPiqpCF+pLHginRLYfnCC58Mu4jklVCgrx8HodpU+Hl0sPE2qmyRcAM78AN0YUwDzYC"
}
},
{
"type": "step",
"result": "=\\frac{1}{2}\\cdot\\:\\int\\:\\frac{2v}{1-v^{2}}dv"
},
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=\\frac{1}{2}\\cdot\\:2\\cdot\\:\\int\\:\\frac{v}{1-v^{2}}dv"
},
{
"type": "interim",
"title": "Apply u-substitution",
"input": "\\int\\:\\frac{v}{1-v^{2}}dv",
"steps": [
{
"type": "definition",
"title": "Integral Substitution definition",
"text": "$$\\int\\:f\\left(g\\left(x\\right)\\right)\\cdot\\:g'\\left(x\\right)dx=\\int\\:f\\left(u\\right)du,\\:\\quad\\:u=g\\left(x\\right)$$",
"secondary": [
"Substitute: $$w=1-v^{2}$$"
]
},
{
"type": "interim",
"title": "$$\\frac{dw}{dv}=-2v$$",
"input": "\\frac{d}{dv}\\left(1-v^{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{d}{dv}\\left(1\\right)-\\frac{d}{dv}\\left(v^{2}\\right)"
},
{
"type": "interim",
"title": "$$\\frac{d}{dv}\\left(1\\right)=0$$",
"input": "\\frac{d}{dv}\\left(1\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
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}
},
{
"type": "interim",
"title": "$$\\frac{d}{dv}\\left(v^{2}\\right)=2v$$",
"input": "\\frac{d}{dv}\\left(v^{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=2v^{2-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "step",
"primary": "Simplify",
"result": "=2v",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYiHI6i/lNYJouYKcylLF6B2k3hxk9aCfAWodBRxXgUexsoRboyLdWbDdDvojbJb4SkeCBKuYKgaNJ253gLI69U5feCPJC8Uak4mwlsl/8zOjPWUEL+I3n8Z72JloyPMrWQ=="
}
},
{
"type": "step",
"result": "=0-2v"
},
{
"type": "step",
"primary": "Simplify",
"result": "=-2v",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:dw=-2vdv$$"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:dv=\\left(-\\frac{1}{2v}\\right)dw$$"
},
{
"type": "step",
"result": "=\\int\\:\\frac{v}{w}\\left(-\\frac{1}{2v}\\right)dw"
},
{
"type": "interim",
"title": "Simplify $$\\frac{v}{w}\\left(-\\frac{1}{2v}\\right):{\\quad}-\\frac{1}{2w}$$",
"input": "\\frac{v}{w}\\left(-\\frac{1}{2v}\\right)",
"steps": [
{
"type": "step",
"primary": "Remove parentheses: $$\\left(-a\\right)=-a$$",
"result": "=-\\frac{v}{w}\\cdot\\:\\frac{1}{2v}"
},
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=-\\frac{v\\cdot\\:1}{w\\cdot\\:2v}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$v$$",
"result": "=-\\frac{1}{w\\cdot\\:2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\int\\:-\\frac{1}{2w}dw"
}
],
"meta": {
"interimType": "Integral U Substitution 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s7+O3P4NyjST8qKRUS5Q9ARQBFOfoHFIkgHkATEbqyRla2NCwimM7dB8C524HvMCB4ymZOc9q9xxqJAg2jt99whbN2Iqnf8o89hIY+/5geo/Se523Vm7Rn9X/LRxylwEtyaN6Hv6MoTMtvtU0IQwXdn84k+SM9uK5ZgVIsXdnKy6Jugs8OYsrd0uK6mBpcEuDFg=="
}
},
{
"type": "step",
"result": "=\\frac{1}{2}\\cdot\\:2\\cdot\\:\\int\\:-\\frac{1}{2w}dw"
},
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\cdot\\:\\int\\:\\frac{1}{w}dw\\right)"
},
{
"type": "step",
"primary": "Use the common integral: $$\\int\\:\\frac{1}{w}dw=\\ln\\left(\\left|w\\right|\\right)$$",
"result": "=\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|w\\right|\\right)"
},
{
"type": "interim",
"title": "Substitute back",
"input": "\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|w\\right|\\right)",
"result": "=\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|\\right)",
"steps": [
{
"type": "step",
"primary": "Substitute back $$w=1-v^{2}$$",
"result": "=\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|1-v^{2}\\right|\\right)"
},
{
"type": "step",
"primary": "Substitute back $$v=\\tan\\left(\\frac{u}{2}\\right)$$",
"result": "=\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(\\frac{u}{2}\\right)\\right|\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=2x$$",
"result": "=\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|\\right)"
}
],
"meta": {
"interimType": "Generic Substitute Back 0Eq"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|\\right):{\\quad}-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|$$",
"input": "\\frac{1}{2}\\cdot\\:2\\left(-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|\\right)",
"result": "=-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|",
"steps": [
{
"type": "step",
"primary": "Remove parentheses: $$\\left(-a\\right)=-a$$",
"result": "=-\\frac{1}{2}\\cdot\\:2\\cdot\\:\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|"
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}\\cdot\\frac{d}{e}=\\frac{a\\:\\cdot\\:b\\:\\cdot\\:d}{c\\:\\cdot\\:e}$$",
"result": "=-\\frac{1\\cdot\\:1\\cdot\\:2\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|}{2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=-\\frac{1\\cdot\\:1\\cdot\\:\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|}{2}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:1\\cdot\\:\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|=\\ln\\left|1-\\tan^{2}\\left(\\frac{2x}{2}\\right)\\right|$$",
"result": "=-\\frac{\\ln\\left|-\\tan^{2}\\left(\\frac{2x}{2}\\right)+1\\right|}{2}"
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=-\\frac{\\ln\\left|-\\tan^{2}\\left(x\\right)+1\\right|}{2}"
},
{
"type": "step",
"result": "=-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
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}
}
],
"meta": {
"solvingClass": "Integrals",
"interimType": "Integrals"
}
},
{
"type": "interim",
"title": "$$\\int\\:\\frac{1}{\\cos\\left(2x\\right)}dx=\\frac{1}{2}\\ln\\left|\\tan\\left(2x\\right)+\\sec\\left(2x\\right)\\right|$$",
"input": "\\int\\:\\frac{1}{\\cos\\left(2x\\right)}dx",
"steps": [
{
"type": "interim",
"title": "Rewrite using trig identities",
"input": "\\int\\:\\frac{1}{\\cos\\left(2x\\right)}dx",
"result": "=\\int\\:\\sec\\left(2x\\right)dx",
"steps": [
{
"type": "step",
"primary": "Use the following identity: $$\\frac{1}{\\cos\\left(x\\right)}=\\sec\\left(x\\right)$$",
"result": "=\\int\\:\\sec\\left(2x\\right)dx"
}
],
"meta": {
"interimType": "Trig Rewrite Using Trig identities 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s74VUWXddkFRJ6FZazpSM+d5CFAOfj2uIfLcNIguBWPJjglS0lOYo+MEX6Bpkgk4kWW2OqI7u8uw/2TDZOKR8MlHIjRu93pF6Ud8rAuy8zIsm9eA3KzDR5LdoQ96EQOWijiBtScDPh1fpDokGg7yx6VK9dDZkXCs5+Cxg1YNvJNPUe9yYF2Q5qSv3gDlLQoBFjj5yGUAwgawpYTH/Vvtg3vE="
}
},
{
"type": "interim",
"title": "Apply u-substitution",
"input": "\\int\\:\\sec\\left(2x\\right)dx",
"steps": [
{
"type": "definition",
"title": "Integral Substitution definition",
"text": "$$\\int\\:f\\left(g\\left(x\\right)\\right)\\cdot\\:g'\\left(x\\right)dx=\\int\\:f\\left(u\\right)du,\\:\\quad\\:u=g\\left(x\\right)$$",
"secondary": [
"Substitute: $$u=2x$$"
]
},
{
"type": "interim",
"title": "$$\\frac{du}{dx}=2$$",
"input": "\\frac{d}{dx}\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=2\\frac{dx}{dx}"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=2\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=2",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYg2sQzwGEAAPyDk8n13Ps8XZGku9zFkxwe1dTH8vycb94wHsFp27x8BxzSfXYcuPllNbbqpyK7JQEZdATEJR51iZ4v02Fm2dNqQJZnxCX4Je"
}
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:du=2dx$$"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:dx=\\frac{1}{2}du$$"
},
{
"type": "step",
"result": "=\\int\\:\\sec\\left(u\\right)\\frac{1}{2}du"
}
],
"meta": {
"interimType": "Integral U Substitution 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s7+kjIfqCK8QGwzUQY8+wMOQsjvX7KVUO/AeCFSId4S33cZqb2ujmN2FEZC5M/msYIHiX35dQ/h01lIvxamZtt5PM+j+1P04cisiXW8HcDKOk4Ruz4fIbA7DSu1jg0w5EAYEFMST8lDZxn1Yq5HMKVTsGLeMxVl55xMYxEfjKBatulcQUlMOhkqQvF9O8Q8/Z5g=="
}
},
{
"type": "step",
"result": "=\\int\\:\\sec\\left(u\\right)\\frac{1}{2}du"
},
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=\\frac{1}{2}\\cdot\\:\\int\\:\\sec\\left(u\\right)du"
},
{
"type": "step",
"primary": "Use the common integral: $$\\int\\:\\sec\\left(u\\right)du=\\ln\\left|\\tan\\left(u\\right)+\\sec\\left(u\\right)\\right|$$",
"result": "=\\frac{1}{2}\\ln\\left|\\tan\\left(u\\right)+\\sec\\left(u\\right)\\right|"
},
{
"type": "step",
"primary": "Substitute back $$u=2x$$",
"result": "=\\frac{1}{2}\\ln\\left|\\tan\\left(2x\\right)+\\sec\\left(2x\\right)\\right|"
}
],
"meta": {
"solvingClass": "Integrals",
"interimType": "Integrals"
}
},
{
"type": "step",
"result": "=-\\left(-\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|-\\frac{1}{2}\\ln\\left|\\tan\\left(2x\\right)+\\sec\\left(2x\\right)\\right|\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "=\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|+\\frac{1}{2}\\ln\\left|\\tan\\left(2x\\right)+\\sec\\left(2x\\right)\\right|",
"meta": {
"solvingClass": "Solver"
}
},
{
"type": "step",
"primary": "Add a constant to the solution",
"result": "=\\frac{1}{2}\\ln\\left|1-\\tan^{2}\\left(x\\right)\\right|+\\frac{1}{2}\\ln\\left|\\tan\\left(2x\\right)+\\sec\\left(2x\\right)\\right|+C",
"meta": {
"title": {
"extension": "If $$\\frac{dF\\left(x\\right)}{dx}=f\\left(x\\right)$$ then $$\\int{f\\left(x\\right)}dx=F\\left(x\\right)+C$$"
}
}
}
],
"meta": {
"solvingClass": "Integrals",
"practiceLink": "/practice/integration-practice#area=main&subtopic=Substitution",
"practiceTopic": "Integral Substitution"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "y=\\frac{1}{2}\\ln\\left|1-\\tan^{2}(x)\\right|+\\frac{1}{2}\\ln\\left|\\tan(2x)+\\sec(2x)\\right|+C"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Multiply by the conjugate of
Take the constant out:
Expand
Apply the Sum Rule:
Simplify
Add a constant to the solution
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is the integral of 1/(cos(x)sin(x)+cos^2(x)) ?
The integral of 1/(cos(x)sin(x)+cos^2(x)) is 1/2 ln|1-tan^2(x)|+1/2 ln|tan(2x)+sec(2x)|+C