What is the derivative of y=2sin(x)+ce^{-x}cos(x) ?

The derivative of y=2sin(x)+ce^{-x}cos(x) is 2cos(x)+c(-e^{-x}cos(x)-e^{-x}sin(x))

What is the first derivative of y=2sin(x)+ce^{-x}cos(x) ?

The first derivative of y=2sin(x)+ce^{-x}cos(x) is 2cos(x)+c(-e^{-x}cos(x)-e^{-x}sin(x))

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derivative of

y = 2 sin (x) + c e^{- x} cos (x)

2 cos (x) + c (- e^{- x} cos (x) - e^{- x} sin (x))

Solution steps

\frac{d}{d x} (2 sin (x) + c e^{- x} cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (c e^{- x} cos (x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (c e^{- x} cos (x)) = c (- e^{- x} cos (x) - e^{- x} sin (x))

= 2 cos (x) + c (- e^{- x} cos (x) - e^{- x} sin (x))

18 y^{^{''}} + 9 y^{^{'}} - 2 y = 0

y^{^{'}} = 3 x^{2} + 1

\frac{5 s - 2}{7 s ^{2} - s - 11}

x \to - \infty lim (x - 2)

\int (x - 6)^{2} (x + 8) d x

What is the derivative of y=2sin(x)+ce^{-x}cos(x) ?
The derivative of y=2sin(x)+ce^{-x}cos(x) is 2cos(x)+c(-e^{-x}cos(x)-e^{-x}sin(x))
What is the first derivative of y=2sin(x)+ce^{-x}cos(x) ?
The first derivative of y=2sin(x)+ce^{-x}cos(x) is 2cos(x)+c(-e^{-x}cos(x)-e^{-x}sin(x))