What is the first derivative of 2x-7 ?

The first derivative of 2x-7 is 2

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derivative of 2x-7

\frac{d}{d x} (2 x - 7)

2

Solution steps

\frac{d}{d x} (2 x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (7)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (7) = 0

= 2 - 0

Simplify

= 2

\int cos^{5} (t) d t

cos (π - 6 x)

y = 2 sin (x) + c e^{- x} cos (x)

18 y^{^{''}} + 9 y^{^{'}} - 2 y = 0

y^{^{'}} = 3 x^{2} + 1