What is (\partial)/(\partial x)(sin(pi(4x-4y))) ?

The answer to (\partial)/(\partial x)(sin(pi(4x-4y))) is cos(pi(4x-4y))*4pi

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(\partial)/(\partial x)(sin(pi(4x-4y)))

\frac{\partial}{\partial x} (sin (π (4 x - 4 y)))

cos (π (4 x - 4 y)) \cdot 4 π

Solution steps

\frac{\partial}{\partial x} (sin (π (4 x - 4 y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (4 x - 4 y)) \frac{\partial}{\partial x} (π (4 x - 4 y))

= cos (π (4 x - 4 y)) \frac{\partial}{\partial x} (π (4 x - 4 y))

\frac{\partial}{\partial x} (π (4 x - 4 y)) = 4 π

= cos (π (4 x - 4 y)) \cdot 4 π

\frac{2}{x}

(\frac{x ^{3}}{x ^{8} + 7})^{2}

h \to 0 lim (h^{4} cos (\frac{3}{h}))

\frac{\partial}{\partial x} (8 e^{x^{8} y})

\int \frac{sec ^{3} ( x )}{tan ^{4} ( x )} d x

What is (\partial)/(\partial x)(sin(pi(4x-4y))) ?
The answer to (\partial)/(\partial x)(sin(pi(4x-4y))) is cos(pi(4x-4y))*4pi