What is the limit as h approaches 0 of h^4cos(3/h) ?

The limit as h approaches 0 of h^4cos(3/h) is 0

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limit as h approaches 0 of h^4cos(3/h)

h \to 0 lim (h^{4} cos (\frac{3}{h}))

0

Solution steps

h \to 0 lim (h^{4} cos (\frac{3}{h}))

Apply the Squeeze Theorem:

0

= 0

\frac{\partial}{\partial x} (8 e^{x^{8} y})

\int \frac{sec ^{3} ( x )}{tan ^{4} ( x )} d x

\frac{d}{d y} (x^{2} + y^{2})

\frac{d}{d x} (\frac{x}{x + 10})

\int (\frac{x + 5}{x ^{2} + 11 x + 18}) d x

What is the limit as h approaches 0 of h^4cos(3/h) ?
The limit as h approaches 0 of h^4cos(3/h) is 0