What is (\partial)/(\partial x)(sin(2y-5x)) ?

The answer to (\partial)/(\partial x)(sin(2y-5x)) is -5cos(2y-5x)

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(\partial)/(\partial x)(sin(2y-5x))

\frac{\partial}{\partial x} (sin (2 y - 5 x))

- 5 cos (2 y - 5 x)

Solution steps

\frac{\partial}{\partial x} (sin (2 y - 5 x))

Treat

y

as a constant

Apply the chain rule:

cos (2 y - 5 x) \frac{\partial}{\partial x} (2 y - 5 x)

= cos (2 y - 5 x) \frac{\partial}{\partial x} (2 y - 5 x)

\frac{\partial}{\partial x} (2 y - 5 x) = - 5

= cos (2 y - 5 x) (- 5)

Simplify

= - 5 cos (2 y - 5 x)

x \to 2 lim (2 x^{2} - 7 x + 5)

\int_{0}^{\frac{1}{3}} x arcsin (3 x) d x

\frac{e ^{x}}{9 x ^{2}}

\frac{d}{d x} (cot (7 x - 3))

x \to - 6 lim (\frac{x ^{2} - 9}{6 - x})

What is (\partial)/(\partial x)(sin(2y-5x)) ?
The answer to (\partial)/(\partial x)(sin(2y-5x)) is -5cos(2y-5x)