What is the limit as x approaches 2 of 2x^2-7x+5 ?

The limit as x approaches 2 of 2x^2-7x+5 is -1

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limit as x approaches 2 of 2x^2-7x+5

x \to 2 lim (2 x^{2} - 7 x + 5)

- 1

Solution steps

x \to 2 lim (2 x^{2} - 7 x + 5)

Plug in the value

x = 2

= 2 \cdot 2^{2} - 7 \cdot 2 + 5

Simplify

2 \cdot 2^{2} - 7 \cdot 2 + 5 : - 1

= - 1

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\frac{e ^{x}}{9 x ^{2}}

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x \to - 6 lim (\frac{x ^{2} - 9}{6 - x})

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What is the limit as x approaches 2 of 2x^2-7x+5 ?
The limit as x approaches 2 of 2x^2-7x+5 is -1