What is the sum from n=3 to infinity of (9/11)^{-n} ?

The sum from n=3 to infinity of (9/11)^{-n} is diverges

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sum from n=3 to infinity of (9/11)^{-n}

n = 3 \sum \infty (\frac{9}{11})^{- n}

diverges

Solution steps

n = 3 \sum \infty (\frac{9}{11})^{- n}

Apply Series Ratio Test:

diverges

= diverges

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What is the sum from n=3 to infinity of (9/11)^{-n} ?
The sum from n=3 to infinity of (9/11)^{-n} is diverges