What is the derivative of-6/((x-1^4)) ?

The derivative of-6/((x-1^4)) is (24)/((x-1)^5)

What is the first derivative of-6/((x-1^4)) ?

The first derivative of-6/((x-1^4)) is (24)/((x-1)^5)

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\frac{d}{d x} (- \frac{6}{( x - 1 ) ^{4}})

\frac{24}{( x - 1 ) ^{5}}

Solution steps

\frac{d}{d x} (- \frac{6}{( x - 1 ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d x} (\frac{1}{( x - 1 ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 6 \frac{d}{d x} ((x - 1)^{- 4})

Apply the chain rule:

- \frac{4}{( x - 1 ) ^{5}} \frac{d}{d x} (x - 1)

= - \frac{4}{( x - 1 ) ^{5}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= - 6 (- \frac{4}{( x - 1 ) ^{5}} \cdot 1)

Simplify

- 6 (- \frac{4}{( x - 1 ) ^{5}} \cdot 1) : \frac{24}{( x - 1 ) ^{5}}

= \frac{24}{( x - 1 ) ^{5}}

\int e^{x - 2 x} sin (x) d x

y^{^{''}} + 4 y^{^{'}} + 4 y = x^{2} + e^{- 2 x}

\int_{0}^{4} \frac{1}{( x - 4 ) ^{2}} d x

\int \frac{4 - ln ( x + 3 )}{x + 3} d x

\frac{d}{d y} (4 x y)

What is the derivative of-6/((x-1^4)) ?
The derivative of-6/((x-1^4)) is (24)/((x-1)^5)
What is the first derivative of-6/((x-1^4)) ?
The first derivative of-6/((x-1^4)) is (24)/((x-1)^5)