What is the tangent of f(x)=4sin(x),\at x= pi/2 ?

The tangent of f(x)=4sin(x),\at x= pi/2 is y=4

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tangent of f(x)=4sin(x),\at x= pi/2

tangent of

f (x) = 4 sin (x), at x = \frac{π}{2}

y = 4

Solution steps

Find the tangent point:

(\frac{π}{2}, 4)

Find the slope of

f (x) = 4 sin (x) : \frac{df ( x )}{d x} = 4 cos (x)

Compute the slope of

f (x) = 4 sin (x)

x = \frac{π}{2} : m = 0

Find the line with slope m=

0

and passing through

(\frac{π}{2}, 4) : y = 4

y = 4

y y^{^{'}} = y^{2} + 1

f (x) = csc^{3} (5 x^{2} + 1)

\int cot^{4} (\frac{1}{2}) t d t

\int \frac{x ^{2} - 9}{x + 3} d x

\int \frac{5 x + 1}{x ^{2} - 6 x + 13} d x

What is the tangent of f(x)=4sin(x),\at x= pi/2 ?
The tangent of f(x)=4sin(x),\at x= pi/2 is y=4