What is the solution for yy^'=y^2+1 ?

The solution for yy^'=y^2+1 is y=sqrt(e^{2t+c_{1)}-1},y=-sqrt(e^{2t+c_{1)}-1}

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yy^'=y^2+1

y y^{^{'}} = y^{2} + 1

y = e^{2 t + c_{1}} - 1, y = - e^{2 t + c_{1}} - 1

Solution steps

y y^{'} (t) = y^{2} + 1

Solve separable ODE:

y = e^{2 t + c_{1}} - 1, y = - e^{2 t + c_{1}} - 1

y = e^{2 t + c_{1}} - 1, y = - e^{2 t + c_{1}} - 1

f (x) = csc^{3} (5 x^{2} + 1)

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What is the solution for yy^'=y^2+1 ?
The solution for yy^'=y^2+1 is y=sqrt(e^{2t+c_{1)}-1},y=-sqrt(e^{2t+c_{1)}-1}