What is the derivative of 1+6x^{3/2} ?

The derivative of 1+6x^{3/2} is 9x^{1/2}

What is the first derivative of 1+6x^{3/2} ?

The first derivative of 1+6x^{3/2} is 9x^{1/2}

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derivative of

1 + 6 x^{\frac{3}{2}}

9 x^{\frac{1}{2}}

Solution steps

\frac{d}{d x} (1 + 6 x^{\frac{3}{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (6 x^{\frac{3}{2}})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (6 x^{\frac{3}{2}}) = 9 x^{\frac{1}{2}}

= 0 + 9 x^{\frac{1}{2}}

Simplify

= 9 x^{\frac{1}{2}}

\frac{d}{d x} (\frac{6 e ^{x}}{5 e ^{x} + 7})

\frac{d}{d x} (a^{x} + x^{a})

\int_{1}^{4} \frac{2 x + 1}{2 x} d x

\frac{d}{d x} (x + 4)

\frac{\partial}{\partial x} (x arctan (\frac{x}{y}))

What is the derivative of 1+6x^{3/2} ?
The derivative of 1+6x^{3/2} is 9x^{1/2}
What is the first derivative of 1+6x^{3/2} ?
The first derivative of 1+6x^{3/2} is 9x^{1/2}