What is the derivative of a^x+x^a ?

The derivative of a^x+x^a is a^xln(a)+ax^{a-1}

What is the first derivative of a^x+x^a ?

The first derivative of a^x+x^a is a^xln(a)+ax^{a-1}

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\frac{d}{d x} (a^{x} + x^{a})

a^{x} ln (a) + a x^{a - 1}

Solution steps

\frac{d}{d x} (a^{x} + x^{a})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{x}) + \frac{d}{d x} (x^{a})

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

\frac{d}{d x} (x^{a}) = a x^{a - 1}

= a^{x} ln (a) + a x^{a - 1}

\int_{1}^{4} \frac{2 x + 1}{2 x} d x

\frac{d}{d x} (x + 4)

\frac{\partial}{\partial x} (x arctan (\frac{x}{y}))

x \to \infty lim (x + x^{3})

\int e^{- s^{2}} d s

What is the derivative of a^x+x^a ?
The derivative of a^x+x^a is a^xln(a)+ax^{a-1}
What is the first derivative of a^x+x^a ?
The first derivative of a^x+x^a is a^xln(a)+ax^{a-1}