What is the integral from-infinity to 0 of e^{-x} ?

The integral from-infinity to 0 of e^{-x} is diverges

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integral from-infinity to 0 of e^{-x}

\int_{- \infty}^{0} e^{- x} d x

diverges

Solution steps

\int_{- \infty}^{0} e^{- x} d x

Compute the indefinite integral:

\int e^{- x} d x = - e^{- x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{- x} d x =

diverges

= diverges

x \to 1 lim (x^{2} + 3 x - 1)

t \to π lim (tan (\frac{5 t}{4}))

y^{^{''}} + 6 y^{^{'}} + 13 y = 0, y (0) = 0, y^{^{'}} (0) = 2

\frac{\partial}{\partial x} (2 ln (x z))

\int ln (x) cos (x) d x

What is the integral from-infinity to 0 of e^{-x} ?
The integral from-infinity to 0 of e^{-x} is diverges