What is area y= 1/x ,y= 1/(x^2),x=3 ?

The answer to area y= 1/x ,y= 1/(x^2),x=3 is ln(3)-2/3

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area y= 1/x ,y= 1/(x^2),x=3

area

y = \frac{1}{x}, y = \frac{1}{x ^{2}}, x = 3

ln (3) - \frac{2}{3}

Decimal Notation

0.43194 \dots

Solution steps

Apply the area formula:

\int_{1}^{3} \frac{1}{x} - \frac{1}{x ^{2}} d x

Solve

\int_{1}^{3} \frac{1}{x} - \frac{1}{x ^{2}} d x : ln (3) - \frac{2}{3}

The area is:

= ln (3) - \frac{2}{3}

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\int \frac{x e ^{x}}{( x + 1 ) ^{2}} d x

\frac{d}{d x} ((5 x^{2} - 8 x) e^{x})

x^{^{''}} - 0 x^{^{'}} + x = 0

\int 6 d x

What is area y= 1/x ,y= 1/(x^2),x=3 ?
The answer to area y= 1/x ,y= 1/(x^2),x=3 is ln(3)-2/3