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Popular >

integral of 1/(x+1)

Solution

\int \frac{1}{x + 1} d x

Solution

ln ∣ x + 1 ∣ + C

Solution steps

\int \frac{1}{x + 1} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x + 1

= ln ∣ x + 1 ∣

Add a constant to the solution

= ln ∣ x + 1 ∣ + C

Popular Examples

maclaurin xe^{x^2}maclaurin

x e^{x^{2}}

integral from 1 to sqrt(x of)sec(t)

\int_{1}^{x} sec (t) d t

derivative of (10/(27x^{8/3)})

\frac{d}{d x} (\frac{10}{27 x ^{\frac{8}{3}}})

tangent of f(x)=(1+4x)^9,(0,1)tangent of

f (x) = (1 + 4 x)^{9}, (0, 1)

derivative of f(x)=-3(2x-2)=0 derivative of

f (x) = - 3 (2 x - 2) = 0

Frequently Asked Questions (FAQ)

What is the integral of 1/(x+1) ?
The integral of 1/(x+1) is ln|x+1|+C