What is the integral from 1 to sqrt(x of)sec(t) ?

The integral from 1 to sqrt(x of)sec(t) is ln|tan(sqrt(x))+sec(sqrt(x))|-ln(tan(1)+sec(1))

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integral from 1 to sqrt(x of)sec(t)

\int_{1}^{x} sec (t) d t

ln tan (x) + sec (x) - ln (tan (1) + sec (1))

Solution steps

\int_{1}^{x} sec (t) d t

Use the common integral:

\int sec (t) d t = ln ∣ tan (t) + sec (t) ∣

= [ln ∣ tan (t) + sec (t) ∣]_{1}^{x}

Compute the boundaries:

ln tan (x) + sec (x) - ln (tan (1) + sec (1))

= ln tan (x) + sec (x) - ln (tan (1) + sec (1))

\frac{d}{d x} (\frac{10}{27 x ^{\frac{8}{3}}})

f (x) = (1 + 4 x)^{9}, (0, 1)

f (x) = - 3 (2 x - 2) = 0

\frac{d}{d x} (\frac{x ^{4}}{4} - 2 x^{2})

(0.1) (2)

What is the integral from 1 to sqrt(x of)sec(t) ?
The integral from 1 to sqrt(x of)sec(t) is ln|tan(sqrt(x))+sec(sqrt(x))|-ln(tan(1)+sec(1))