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Popular >

y^'=e^{3x+y}

Solution

y^{^{'}} = e^{3 x + y}

Solution

y = - ln (- \frac{1}{3} e^{3 x} - c_{1})

Solution steps

y^{'} (x) = e^{3 x + y}

Solve separable ODE:

y = - ln (- \frac{1}{3} e^{3 x} - c_{1})

y = - ln (- \frac{1}{3} e^{3 x} - c_{1})

Popular Examples

derivative of (3x^{1/2}/2)

\frac{d}{d x} (\frac{3 x ^{\frac{1}{2}}}{2})

integral of x(e^{-5x})

\int x (e^{- 5 x}) d x

derivative of y=ln(7x)derivative of

y = ln (7 x)

integral of sqrt(x)sqrt(49-x)

\int x 49 - x d x

sum from n=0 to infinity of 5

n = 0 \sum \infty 5

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{3x+y} ?
The solution for y^'=e^{3x+y} is y=-ln(-1/3 e^{3x}-c_{1})